Charles Woodson NFC Defensive Player of the Week… Again
Green Bay Packers’ cornerback Charles Woodson was named the NFC Defensive Player of the Week for the second time this season.
In addition to winning the award for his performance against the Detroit Lions, he also won it for his play in the Packers win over the Dallas Cowboys.
Against Detroit, Woodson registered seven tackles, a sack, two interceptions, a forced fumble and a touchdown. Woodson had a similar stat line against Dallas – nine tackles, a sack, an interception and two forced fumbles.
The second player of the week award goes nicely with the NFC Defensive Player of the Month award, which Woodson won for the month of September.
As we’ve noted, and taken crap for from some Jared Allen homers, Woodson is making a strong case for the NFL’s Defensive Player of the Year.
That stupid hillbilly is having a nice year, no doubt, but I wouldn’t put him any higher than third on the DPOY list at this point of the season. Allen has 12.5 sacks, 7.5 of which came against your Green Bay Packers. In five games this season he hasn’t had any sacks.
I know Vikings’ fans will have some idiotic reasons why Allen still deserves the award more than Charles, but check back later and I’ll break down the race in depth.
Then you Vikings’ fans can kick the dirt, pout because you know you’re wrong, and say, “oh yeah, well our team is better than yours!”
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